where σ determines the distance at which the two particles are at equilibrium, and ε is the strength of the interaction. The first term is responsible for the repulsion at short distance and the second term is responsible for the attraction at long distance. A plot of the Lennard-Jones potential is shown below.
The force is defined by F(r) = -∂U/∂r, so the force associated with the Lennard-Jones potential is
A sketch of the force associated with the Lennard-Jones potential is shown below.
By setting the force expression to zero, it is possible to show that the equilibrium distance for the Lennard-Jones potenial is 21/6σ and that the potential at this distance is -ε.
One practical problem with the Lennard-Jones potential is that it has infinite range. It is impossible for two particles go far enough apart to escape their attractive force. The force gets infinitely weak at large distance, so this is not a physical problem. But from a computational point of view, it means that the force must be calculated for every pair of particles in the system. This will limit the speek of the computation for large systems. For this reason, the Lennard-Jones force is often cut off at a finite distance, often about 3σ. The effect on the dynamics is small, but the speed-up of the computation can be dramatic.
There are cases where only the hard-sphere repulsion of the Lennard-Jones potential is necessary (for instance, in our simulation of the crystal). In such cases, we can either cut off the force at the equilibrium distance so there is no attractive force, or simply omit the attractive term from the potential.